Free energy change to percent converted
Type a value in kJ/mol to get it in % instantly.
99.9%
That's 990× as favorable as a balanced reaction, while a favorable reaction is 1.01× more favorable. At equilibrium about 99.9% has reacted.
What it means
Which way does it go?
Values are at 25 °C. Free energy scales with temperature, so the same K means a different ΔG° in a furnace.
The math
How to convert kJ/mol to %
The constant and the free energy are the same statement: ΔG° = −RT ln K, which at 25 °C is ΔG° = −5.708 × log₁₀K kJ/mol.
Example: -17.1 kJ/mol = 99.8991 %.
Every unit
Your equilibrium in every unit
Tables
kJ/mol to % conversion table
| kJ/mol | % |
|---|---|
| -68.5 kJ/mol | 100 % |
| -57.1 kJ/mol | 100 % |
| -34.2 kJ/mol | 99.9999 % |
| -17.1 kJ/mol | 99.8991 % |
| -5.71 kJ/mol | 90.9157 % |
| 0 kJ/mol | 50 % |
| 5.71 kJ/mol | 9.08428 % |
| 17.1 kJ/mol | 0.100872 % |
| 34.2 kJ/mol | 0.000101957 % |
| 57.1 kJ/mol | 9.92×10⁻⁹ % |
% to kJ/mol conversion table
| % | kJ/mol |
|---|---|
| 1×10⁻⁸ % | 57.0801 kJ/mol |
| 0.0001 % | 34.2481 kJ/mol |
| 0.0999 % | 17.124 kJ/mol |
| 9.09 % | 5.70828 kJ/mol |
| 50 % | 0 kJ/mol |
| 90.9 % | -5.70528 kJ/mol |
| 99.9 % | -17.1215 kJ/mol |
Quick answers
Quick answers
- How many % is 1 kJ/mol?
- 1 kJ/mol is 40.0497 %.
- How many % is 10 kJ/mol?
- 10 kJ/mol is 1.73962 %.
- How many % is -17.1 kJ/mol?
- -17.1 kJ/mol is 99.8991 %.
The units
About these units
Free energy change (kJ/mol)
ΔG° at 25 °C. Negative means the reaction goes forward.
Percent converted (%)
How much has reacted at equilibrium, for a simple A ⇌ B.
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